5c^2-34c-7=0

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Solution for 5c^2-34c-7=0 equation:


Simplifying
5c2 + -34c + -7 = 0

Reorder the terms:
-7 + -34c + 5c2 = 0

Solving
-7 + -34c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-1 + -5c)(7 + -1c) = 0

Subproblem 1

Set the factor '(-1 + -5c)' equal to zero and attempt to solve: Simplifying -1 + -5c = 0 Solving -1 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -5c = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -5c = 0 + 1 -5c = 0 + 1 Combine like terms: 0 + 1 = 1 -5c = 1 Divide each side by '-5'. c = -0.2 Simplifying c = -0.2

Subproblem 2

Set the factor '(7 + -1c)' equal to zero and attempt to solve: Simplifying 7 + -1c = 0 Solving 7 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1c = 0 + -7 -1c = 0 + -7 Combine like terms: 0 + -7 = -7 -1c = -7 Divide each side by '-1'. c = 7 Simplifying c = 7

Solution

c = {-0.2, 7}

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